std::countl_zero

From cppreference.com
< cpp‎ | numeric
Defined in header <bit>
template< class T >
constexpr int countl_zero( T x ) noexcept;
(since C++20)

Returns the number of consecutive 0 bits in the value of x, starting from the most significant bit ("left").

This overload participates in overload resolution only if T is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).

Parameters

x - values of unsigned integer type

Return value

The number of consecutive 0 bits in the value of x, starting from the most significant bit.

Example

#include <bit>
#include <bitset>
#include <cstdint>
#include <iostream>
 
int main()
{
    for (const std::uint8_t i : { 0, 0b11111111, 0b11110000, 0b00011110 }) {
        std::cout << "countl_zero( " << std::bitset<8>(i) << " ) = "
                  << std::countl_zero(i) << '\n';
    }
}

Output:

countl_zero( 00000000 ) = 8
countl_zero( 11111111 ) = 0
countl_zero( 11110000 ) = 0
countl_zero( 00011110 ) = 3

See also

counts the number of consecutive 1 bits, starting from the most significant bit
(function template)
counts the number of consecutive 0 bits, starting from the least significant bit
(function template)
counts the number of consecutive 1 bits, starting from the least significant bit
(function template)
(C++20)
counts the number of 1 bits in an unsigned integer
(function template)
(C++11)  
checks if all, any or none of the bits are set to true
(public member function of std::bitset<N>)